When performing today\'s lab, you measure the temperature of the lab during the

Question

When performing today's lab, you measure the temperature of the lab during the calibration of the graduated cylinder. You record the temperature as 2 degrees lower than it actually is. How will this error affect the calculated density (will the resulting calculated density be too high, too low or unaffected)?

Density of the sucrose solution would be too high. This is because when the temperature is reported too low, the density used in Table 1 would be too high. When water's density is too high in the calculations, the volume would be calculated as too low. If the volume delivered is calculated as too low, the density of the sucrose solution would be too high.

Density of the sucrose solution would be too low. With the temperature reported too low, the volume of water would seem too high. If the volume is too high, the calculated density of the sucrose solution would be too low.

The density of sucrose would be unaffected because temperature does not affect density.; The density of the sucrose solution would be unaffected. Even though the volume is affected, the mass would also change proportionally.

which is correct?

Explanation / Answer

density = mass / Volume

when Temperature is increased ... Volume increases which leads to decrease in density

ANswer is :

Density of the sucrose solution would be too high. This is because when the temperature is reported too low, the density used in Table 1 would be too high. When water's density is too high in the calculations, the volume would be calculated as too low. If the volume delivered is calculated as too low, the density of the sucrose solution would be too high

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