10 grams of compound A whose molar mass is 50 g mol^-1 are dissolved in 180 g of

Question

10 grams of compound A whose molar mass is 50 g mol^-1 are dissolved in 180 g of water. Therefore, we know that the solution molality (m) and the solute mole fraction, X_A, are such that 0.0 lessthanorequalto X_A lessthanorequalto 0.05 and 0.0 lessthanorequalto m lessthanorequalto 050 molal 0.05 lessthanorequalto X_A lessthanorequalto 0.10 and 0, 5 lessthanorequalto m lessthanorequalto 1.0 molal. 0.01 lessthanorequalto X_A lessthanorequalto 0.02 and 1.0 lessthanorequalto m lessthanorequalto 1.3 molal. 0.01 lessthanorequalto X_A lessthanorequalto 0.02 and 1.3 lessthanorequalto m lessthanorequalto 1.6 molal X_A > 0.025 and m > 1.0 molal.

Explanation / Answer

molality = (W/MW)(1000 / mass of solvent in g)

molality = (10 / 50) (1000 / 180)

molality = 0.2 x 5.55

molality = 1.1 m

moles of A = 10 / 50 = 0.2

moles of B = 180 /18 = 10

XA   = 0.2 / 0.2+10 = 0.2 / 10.2

XA  = 0.02

answer = option C

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