C 2 H 5 NH 3 + < C 5 H 5 NH + < C 6 H 7 OH C 5 H 5 NH + < C 6 H 7 OH < C 2 H 5 N

Question

C2H5NH3+< C5H5NH+ < C6H7OH

C5H5NH+< C6H7OH < C2H5NH

C6H7OH < C2H5NH3+< C5H5NH+

C6H7OH < C5H5NH+ < C2H5NH

C5H5NH+< C2H5NH3+ < C6H7OH

The solution is acidic.

The solution is neutral.

The solution is a strong oxidant.

The values for Ka and Kb for the species in solution must be known before a prediction can be made.

The solution is basic.

Al2O3

PbO

SO2

CaO

H2O

NH2

NH4

NH2+

NH2–

NH4+

Consider the weak bases below and their Kb values: C6H7O– Kb = 1.3 × 10–10 C2H5NH2 Kb = 5.6 × 10–4 C5H5N   Kb = 1.7 ×10–9 Arrange the conjugate acids of these weak bases in order of increasing acid strength.

Explanation / Answer

1)
lower the value of Kb, weaker will be the base and hence stronger will be its conjugate acid
Kb order is:
C2H5NH2 > C5H5N > C7H7O-

so, acidic strength order of conjugate acid will be:
C2H5NH3+< C5H5NH+ < C6H7OH

2)
Since KCl is salt of KOH and HCl, both are strong base and strong acid respectively
Hence KCL will be neutral
Answer:
The solution is neutral.

3)
acidic oxide is mainly for non metals
Answer: SO2

4)
Conjugate base is formed after losing H+
Answer:
NH2-

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