The densities of crystalline CO2 and H2S at 160 K are 1.56 and 0.95 g/cm3, respe

Question

The densities of crystalline CO2 and H2S at 160 K are 1.56 and 0.95 g/cm3, respectively. Calculate their molar volumes.

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Are the molar volumes in the solid state as similar as they are in the gaseous state? Explain. No, they are not. In the solid state, most of the empty space is gone, so molecular characteristics do influence molar volumes. Yes, they are. Even though in the solid state most of the empty space is gone, intermolecular forces are almost uncorrelated with molecular characteristics. Yes, they are. The molecules are still far apart in the solid state. No, they are not. In the solid state, there is no empty space in the occupied volume and the molar volume depends solely on the size and shape of particles. Submit My Answers Give Up artE Would you expect the molar volumes in the liquid state to be closer to those in the solid or gaseous state? The molar volumes in the liquid state are closer to those in the solid state than those in the gaseous state. The molar volumes in the liquid state are closer to those in the gaseous state than those in the solid state.

Explanation / Answer

Solution

As we know that molar volume is the volume occupied by 1 mole of the substance.

(i) Density of CO2 at 160 K = 1.56 g/cm3

The molar mass of CO2 = 44 g/mol

The molar volume of CO2 (volume occupied by 44 g CO2) = mass /density = 44 g mol-1/1.56 g cm-3

= 28.2 cm3 mol-1 (since 1.0 cm3 = 1.0 mL)

= 28.2 mL mol-1 = (28.2/ 1000) L mol-1 = 0.0282 L mol-1(answer)

(ii) Density of H2S at 160 K = 0.95 g/cm3

The molar mass of H2S = 34 g/mol

The molar volume of H2S (volume occupied by 34 g H2S) = mass /density = 34 g mol-1/0.95 g cm-3

= 35.789 cm3 mol-1   (since 1.0 cm3 = 1.0 mL)

= 35.789 mL mol-1 = (35.789/ 1000) L mol-1 = 0.03578 L mol-1(answer)

1) “No they are not. In the solid state, most of the empty space is gone, so molecular characteristics do the influence molar volume” is correct.

2) “The molar volumes in the liquid state are closer to those in the solid state than those in the gaseous state” is correct.

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