I need help filling in the table. It would be nice if some kind people can expla

Question

I need help filling in the table. It would be nice if some kind people can explain the calculations in details while filling in answers.

Standard Solutions Table I in Part A of the procedure is reproduced below initial molarity (M) of Fe and SCN 2+ M) sent in the 25.00 mL ples of each of the five standard solutions olar concentration of FesCN Calculate and enter the and the final' Table I Solution 10.00 10.00 10.00 10.00 10.00 Volume (mu) of o.150 M Fe3+ in o.10 M HNO3 0.00 volume (mL) of 5.00 x 10 4 M scN1 in o.10 M HNO3 2.00 7.00 9.00 [Fe3+]o (M 'initial' in 25 mL) [SCN lo (M 'initial' in 25 mL) M of eSCN nal

Explanation / Answer

Fe3+ + SCN- <===> [FeSCN]2+

Molarity of [Fe3+]o stock = 0.150 M

after dilution the [Fe3+]o concentration = 0.150 M x 10 ml/25 ml = 0.06 M

25 ml is final volume of solution

Similarly,

[SCN-]o = 5 x 10^-4 M x 2 ml/25 ml = 4 x 10^-5 M

SCN- is the limiting reactant here

1 mole of SCN- would produce 1 mole of [FeSCN]2+

so, filling the table accordingly

Solution             1                   2                   3                   4                    5

[Fe3+]o            0.06             0.06              0.06               0.06                 0.06

[SCN-]o              0            4 x 10^-5       1 x 10^-4      1.4 x 10^-4      1.8 x 10^-4

[FeSCN]2+         0            4 x 10^-5       1 x 10^-4      1.4 x 10^-4      1.8 x 10^-4

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