6. What is the change in entropy for a typical, 65 kg human (assume the body has

Question

6. What is the change in entropy for a typical, 65 kg human (assume the body has the same physical properties as water) when the body core temperature is lowered from normal (37 degree Celsius) to a moderate-severe hypothermic state (32 degrees Celsius)?

7. Prion protein unfolds at the transition temperature of 60.1 degrees Celsius, and the standard enthalpy of transition is 124.8 kJ/mol. Calculate the entropy of unfolding of prion protein at 37 degrees Celsius, given that the difference in constant pressure heat capacities on unfolding is 8.21 kJ/mol*K and can be assumed to be independent of temperature

Please show all work. Thank you

Explanation / Answer

1.change in entropy = mass*Cp* ln (T2/T1)= 65*4.184*ln[(32+273)/(37+273)]=-4.42 K/K

2. Entropy change at transition temperature = enthalpy of transition/Temperature in K= 124.8/(60.1+273)= 0.375 KJ/mol.K

entropy during change in temperature = 8.21*ln(37+273)/(60.1+273) =-0.59 Kj/mol.K

change in entropy = 0.375-0.590 = -0.215 Kj/mole.K

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