The following data are for the reaction 2NO (g) + O_2 (g) rightarrow 2NO_2 (g) a

Question

The following data are for the reaction 2NO (g) + O_2 (g) rightarrow 2NO_2 (g) at some temperature. Experiment 1: [NO] = 0.0060 M; [O_2] = 0.0060 M; rate = 6.0 times 10^-1 M/s. Experiment 2: [NO] = 0.0060 M; [O_2] = 0.012 M; rate = 1.2 M/s. Experiment 3: [NO] = 0.012 M; [O_2] = 0.0060 M; rate = 2.4 M/s. Determine: The order of the reaction with respect to nitrogen monoxide: order = The order of the reaction with respect to oxygen: order = The value of the rate constant for the reaction at this temperature:

Explanation / Answer

a)
see experiment 1 and 3
[NO] doubles and [O2] is constant
rate becomes 4 times
so order of [NO] is 2
Answer: 2

b)
see experiment 1 and 2
[NO] is constant and [O2] doubles
rate becomes 2 times
so order of [O2] is 1
Answer: 1

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.