On the basis of only solubility behavior (i.e. without forming complex ions or u

Question

On the basis of only solubility behavior (i.e. without forming complex ions or use a redox reaction's), design a practical scheme for isolating each ion in the following mixtures. Assume each ion is initially present at about 0.1 M, and each one should be isolated as a different solid compound. Do not redissolve any precipitate. You may skip confirmatory test for this exercise. You may use any common lab reagent. A) Ag, Hg B) Ba,Fe C)Pb, Zn, Mg
On the basis of only solubility behavior (i.e. without forming complex ions or use a redox reaction's), design a practical scheme for isolating each ion in the following mixtures. Assume each ion is initially present at about 0.1 M, and each one should be isolated as a different solid compound. Do not redissolve any precipitate. You may skip confirmatory test for this exercise. You may use any common lab reagent. A) Ag, Hg B) Ba,Fe C)Pb, Zn, Mg
On the basis of only solubility behavior (i.e. without forming complex ions or use a redox reaction's), design a practical scheme for isolating each ion in the following mixtures. Assume each ion is initially present at about 0.1 M, and each one should be isolated as a different solid compound. Do not redissolve any precipitate. You may skip confirmatory test for this exercise. You may use any common lab reagent. A) Ag, Hg B) Ba,Fe C)Pb, Zn, Mg

Explanation / Answer

a)

Add HCl, so

Ag+ + Cl- = AgCl(s)

and

Hg2+ + 2Cl- = Hg2Cl2 preciptiates

Add aqeous ammonia NH3(aq)

so

AgCl8(s) + 2 NH3 = Ag(NH3)2Cl (aq) , this will be soluble

Hg2Cl2(s) + 2 NH3 = Hg(s) + HgNH2Cl(aq) + NH4Cl prcipitate will be separated as Hg(s)

b)

Add SO4-2 from H2SO4, so

Ba+2 ions + SO4-2 = BaSO4(s) precipitate

then, filter

Fe+3 solution remains

Add (OH-) from NAOH (basic solution) in order to form Fe(OH)3(s)

c)

Add HCl, Cl- ions precipitate Pb+2 via PbCl2

then

for Zn:

Add H2S, so S-2 ions are present

then

ZnS(s) precipitates, filter and

remaining solution has Mg+2 ions

so

Add CO3-2 from H2CO4 or NA2CO3

this should precipitate MgCO3(s)

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