I WOULD APPRECIATE IF YOU GUYS DO #8, and 9. All the STEPS shown please IF DONE
ID: 483737 • Letter: I
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I WOULD APPRECIATE IF YOU GUYS DO #8, and 9. All the STEPS shown please IF DONE CORRECTLY I WILL GIVE GREAT FEEDBACK WHICH IM SURE OF. Thank you so much. 8. The conversion of cyclopropane to cyclopropene is a first order reaction. The rate constant is k 6.7 x 10 si and the initial concentration of cyclopropane is 0.03 a. What is the concentration of cyclopropane after 37 minutes? b. hat is the half-life for this reaction (in seconds)? 9. A second order reaction has a rate constant of kr 0.0023 Misri. Find the halflife if the initial concentration is 0.025 M.Explanation / Answer
8) K = 6.7*10-4 s-1
[Ao] = 0.0300M = initial concentration of cyclopropane
a) Concentration after 37 min ; t = 37 min = 2220 sec
For first order reaction,
[At] / [Ao] = e-Kt where [At] is the concentration of cyclopropane after 37 min
[At] / 0.0300 = e ^(-6.7*10-4 * 2220)
[At] / 0.0300 = 0.225959
[At] = 6.77878*10-3 M = concentration of cyclopropane after 37 min
b) for first order reactions t1/2 = 0.693 / K
t1/2 = 0.693 / 6.7*10-4 = 1034.328 = 1034 sec approx
9) K = 0.0023 M-1s-1
Initial concentration [Ao] = 0.025 M
For second order reaction, t1/2 = 1 / K [Ao]
Half life , t1/2 = 1 / (0.0023 * 0.025 ) = 17391.304 sec = 17391 sec approx
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