The salicylic acid reactant is a while solid. Handle it as a toxic irritant. It

Question

The salicylic acid reactant is a while solid. Handle it as a toxic irritant. It will be the limiting reactant. and about 2.0-2.2 g will be weighed. The second reactant, acetic anhydride, is a liquid. It is a corrosive lachrymal or and must always be kept under a fumehood (What does the term lack Look it up.) Acetic anhydride is destroyed by water, so keep the reaction mixture under the after the water is added. The amount of acetic anhydride needed for the reaction must be calculated. Assume 2.0 g of salicylic acid will be used. Calculate the moles of salicylic acid using its molar mass. Use the mole ratio from the chemical equation to determine the ideal moles of acetic anhydride. Then multiply the answer by three to obtain an excess of the acetic anhydride. Convert the moles of acetic anhydride to mass in grams using its molar mass. Convert the mass to volume in mL using the density of acetic anhydride, which is 1.082 g/mL. Finally, round the volume to the nearest 0.1 mL so it can be measured in the lab.

Explanation / Answer

1. number of moles = mass/ molar mass

= 2 gm/ 138 gm/mol

= 0.0145 moles

2. According to reaction, 1 mol salicylic acid reacts with 1 mol acetic anhydride. So, moles of acetic anhydride = 0.0145 moles

Now, 0.0145 *3 = 0.0435 moles

moles of anhydride used = 0.0435 - 0.0145 = 0.029moles

3. mass of acetic anhydride = 0.0435 mol * 102.1 gm/mol

= 4.5 gm

4. volume = mass /density

= 4.5 gm / 1.082 gm/ml

= 4.2 ml

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