Lab 6: Synthesis of 1-Bromobutane Prelab Assignment-Due at the beginning of lab

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Lab 6: Synthesis of 1-Bromobutane Prelab Assignment-Due at the beginning of lab 1. Read this handout and Guide to Success in the Organic Chemistry Lab before starting. 2. Print and complete the Prelab 6 Question Sheet, and turn in at the start of lab 3. Complete the following in your lab notebook IN PEN: a. Table of Contents: Find (or create) the Table of Contents at the front of the notebook: add the lab lab title, and the page for the first page of this lab report. b. Header information: Add to the top of the report's 1st page c. I. Introduction: Write this in your own words; do not copy this handout! d. II. Procedure: Write this in your own words; do not copy this handout! e. Ill. Results: Begin this section, ready to record observations INTRODUCTION In this experiment, you will convert a primary alcohol into a primary alkyl bromide, using a bimolecular nucleophilic substitution (SN2) reaction. Substitution reactions, in which one atom or group of atoms replaces another, are commonly observed for organic compounds. Many substitution reactions involve a kind of reacting group called a nucleophile. Anucleophile contains an unshared pair of electrons that reacts with a site in an organic molecule, called an electrophile, that is electron deficient. Nucleophilic substitution reactions share several characteristics with acid-base reactions, as shown in Figure 1. B-H weak weak strong strong base acid acid base (Figure 1) Nu-C leaving organic nucleophile organic reactant group product Groups that are good leaving groups in nucleophilic substitution reactions are weak bases in acid-base reactions. Strong bases are typically good nucleophiles in substitution reactions. In a Bronsted-Lowry acid-base reaction, a proton is transferred from the conjugate acid of a weak base to a strong base. In a similar fashion, nucleophilic substitution reactions often involve the transfer of a carbon group from a weak base, the leaving group, to a stronger base, the

Explanation / Answer

Anhydrous CaCl2 is a dehydrating agent. You have used water in previous ateps. Although , you have pipetted out the aquous layer in step 6 and 7, some water molecule can still be trapped in organic layer. If you see you organic layer is cloudy this means that it has some water molecule trapped in it.

Anhydrous CaCl2 will absorb this water molecules to form CaCl2. 6H2O (Hydrated CaCl2) and your compound will be dry.The organic layer will become clear as you add CaCl2.

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