The oxidation number of an element is the \"charge\" the element would have if a

Question

The oxidation number of an element is the "charge" the element would have if all of its bonds were completely ionic; that is, if the electron pairs of each bond were transferred to the more electronegative atom. For monotomic ions the oxidation number is simply the charge of the ion. For covalently bonded elements the oxidation number is a bookkeeping device and does not mean that the element carries an actual charge. Determine the oxidation state for each of the elements below. The oxidation state of nitrogen in nitrogen dioxide NO_2 is. The oxidation state of manganese in manganese(?) oxide Mn_2O_3 is. The oxidation state of nitrogen in potassium nitride K_3N is .

Explanation / Answer

1. The oxidation no of Nitrogen in Nitrogen dioxide(NO2) is + 4

2. The oxidation no of Manganese in Manganese Oxide (Mn2O3) is +3

3.The oxidation No of Nitrogen in potassium Nitride(K3N) is -3

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