92% Sun 3:32 PM a E Chrome File Edit View History Bookmarks People Window Help O

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92% Sun 3:32 PM a E Chrome File Edit View History Bookmarks People Window Help O M. Barry University CHE 112 x C Chegg Study I Guided solution X Atlantis C www.saplinglearning-Com biscms/mod/ibis/view.php?ida3153049 Semester 1 (Barry U) 2/19/2017 0:55 PM A 3.9/10 Gradebook Attempts Score Print Calculator Periodic Table 100 Question 8 of 17 95 Sapling Learning semester 2 (Barry U) 3 100 The Ka of a monoprotic weak acid is 343 x 103. What is the percent ionization of a 0.116 M solution of this acid? 75 Number Semester 3 (Barry U) 95 100 emester 4 (Barry U) 13 0 Hin O Previous Give Up & View Solution 2 Check Answer Next Ext

Explanation / Answer

The Ka is given to be 3.43 x 10 -3 and C = 0.115M

For a weak acid HA <--------> H+ + A-

C 0 0 initial concentration

C(1-x) Cx Cx after ionisation

where x is the degree of ionisation.

Thus Ka = [Cx][Cx] / [C(1-x)] As degree of ionisation of weak acid x is verysamll compared to C

Ka = Cx2 or degree of ionisation x = square root of (Ka/C)

Thus x = (3.43x10-3/0.116)1/2

=1.72x10-2

percent ionization = 1.72 x10-2x100 = 1.72 %

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