Given that Kp for the reaction below is 1.0 x 105 estimate the Go at room temper

Question

Given that Kp for the reaction below is 1.0 x 105 estimate the Go at room temperature. How does this value compare to that obtained from the tables? (two separate calculation)

                   N2(g) + 3 H2(g)    2 NH3(g)
‘
3. For the same reaction and conditions above, if the Nitrogen partial pressure was 0.60 atm and the hydrogen partial pressure was 0.60 atm, what would the pressure of ammonia need to be to be at equilibrium?

i already have the first part figured out i just need number 3 answered

Explanation / Answer

Kp = ( pNH3)^2 / ( pN2 x pH2^3 )

10^- 5 = ( pNH3)^2 / ( 0.6 x 0.6^3)         ( Its given Kp = 10^5 but its may be type error since in general Kp = 10^-5 for this reaction)

pNH3 = 0.00114 atm = 1.14 x 10^-3 atm

Related Questions

Navigate

• Browse (All)
• Browse G
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.