A sample consisting of 2.0 mol CO2 occupies a fixed volume of 15.0dm^3 at 300K.

Question

A sample consisting of 2.0 mol CO2 occupies a fixed volume of 15.0dm^3 at 300K. When it is supplied with 2.35kJ of energy as heat, its temperature increases to 341K. Assume CO2 is described by van der Waals equation of state, and calculate w, q and delta U. A sample consisting of 2.0 mol CO2 occupies a fixed volume of 15.0dm^3 at 300K. When it is supplied with 2.35kJ of energy as heat, its temperature increases to 341K. Assume CO2 is described by van der Waals equation of state, and calculate w, q and delta U.

Explanation / Answer

Here

Volume= constant

So Work =PdV=0

Heat q = 2.35 kJ given

Now according to first law of thermodynamics

Internal enrgy defined as:

U=q-w

U=q=2.35 kJ

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