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saplinglearnin x Indiana State U x www sap linglearnin x CQ2: write The Follo x C www.sap inglearning.com mod Vibis/view.php?id 3224075 /ibiscm 2/20/2017 12:00 PM N26 4/10o Gradebook Assignment Information Attempts Score Print Calculator Periodic Table Available From: 2/10/2017 10:00 AM Question 7 of 2/20/2017 12:00 PM Due Date: Sapling Learning Points Possi ble 00 Grade Category: Default Consider the following set cate measurements Description 18.7 g, 19.2 g, 17.9 g, 19.8 g. 8.3 g, 18.9 g Policies: SFW Custom For this data set, calculate each of the following: You can check your answers. a) the mean d) the standard deviation (s) You can view solutions when you complete or give up on any question. Number Number You can keep trying to answer each question until you get it right or give up. e) the coefficient of variation (CV) b) the median You lose 10% of the points available to each answer in your question for each incorrect attempt Numb Number at that answer eTextbook c) the spread or range (w) Number O Help With This Topic O Web Help & Videos O Technical Support and Bug Reports A Previous Give Up 8 View Solution Check Answer Next SExit Sapling Learning Inc. about us careers partners privacy policy terms of use contact us help aExplanation / Answer
Given, the set of replicate measurement as 18.7g, 19.2g, 17.9g, 19.8g, 19.3g, 18.9g
(18.7 + 19.2 + 17.9g +19.8g + 19.3g + 18.9g)/6 = 113.8g/6 = 18.97g
b) The median is the middle value in a set of values.
Arranging the measurement in descending order, 19.8g, 19.3g, 19.2g, 18.9g, 18.7, 17.9
19.2g and 18.9g are in the middle and median should be the average of two i.e., (19.2+18.9)g/2 = 19.05g
c) The range is the difference between the largest and smaller values.
19.8-17.9 = 1.9g
d) The standard deviation is the average distance between each data point and the mean.
Sqrt[((18.7-18.97)2 + (19.2-18.97)2 + (17.9-18.97)2 + (19.8-18.97)2 + (19.3-18.98)2 + (18.9-18.97)2)/6]
= sqrt[(0.0729 + 0.0529 + 1.145 + 0.689 + 0.102 + 0.0049)/6]
= sqrt[2.067/6] = sqrt(0.3445) = 0.587g
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