Same data You and partner independently calculate the unknown molar mass using t

Question

Same data You and partner independently calculate the unknown molar mass using the this same date. You both get different results. What would be the main source for this difference? Suppose your thermometer consistently read a temperature of 1.5 degree C lower than the correct temperature throughout the experiment, flow will this affect the molar mass determination? If the freezing point of the solution had been incorrectly read 0.3 degree C lower than the true freezing point, would the molar mass you calculate be larger or smaller that the true value? Explain your answer.

Explanation / Answer

1) Since you had the same data's, it will due to calculation mistake

2) The depression of freezing point as well as elevation of boiling point is represented as the change in temperature and not as the exact temperatures. This change in temperature is related to concentration and thereby molar mass of unknown. Here there are 2 situations. If both quantities, the actual freezing / boiling point and new boiling/ freezing point, are measured 1.5 degree Celsius less than their respective original value then there won't be any effect on the value of molar mass.

If the new freezing point alone is measured 1.5degree Celsius less than the original value, the change in temperature increases and this is directly proportional to molality and inversely proportional to molar mass. Therefore molar mass show a less value than actual value.

3) Here also the molar mass will decrease because the change of temperature is inversely proportional to the molar mass. (T= Kfm=Kf*given mass / molar mass * mass o ssolventin kg)

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