A 1.0 ml. sample of 0.0050 M 12 solution is mixed with 1.0 ml. of 4.0 M acetone
ID: 486845 • Letter: A
Question
A 1.0 ml. sample of 0.0050 M 12 solution is mixed with 1.0 ml. of 4.0 M acetone solution. 1.0 ml. of 1.0 M HCI solution, and 2.0 ml. water. What is the molarity of the acetone in the resulting solution? A reaction starts with 5.0 times 10^-5 M crystal violet. After 205 minutes have passed, there is not trace of purple color. (We can assume the CV completely reacted) Calculate the average rate of reaction for the crystal violet. Use the method of initial rates and the experimental data presented in the table below to determine the rate law for the reaction of A + B rightarrow C.Explanation / Answer
3)
given: intial concentration of Crystal violet = 5 * 10-5 M = 5 * 10-5 mol/L
time for complete reaction is 205 min
so average rate of reaction = 5 * 10-5 mol/L / 205 min = 2.44 * 10-7 mol/L.min answer
4)
given concentrations
A B Rate (M/min)
2.2 * 10-4 M 2.2 * 10-4 M 2.9 * 10-8
6.7 * 10-4 M 2.2 * 10-4 M 2.7 * 10-7
2.2 * 10-4 M 1.1 * 10-4 M 1.4 * 10-8
Rate is R = k [A]2 [B]
where k = 2.9 * 10-8 M/min / ((2.2 * 10-4 M)2 * 2.2 * 10-4 M) = 0.272 * 104 (/M.min)
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