Question 1 Given that 4.0x10 -5 moles of S 2 O 3 2- were consumed, calculate the

Question

Question 1

Given that 4.0x10-5 moles of S2O32- were consumed, calculate the Rate for the kinetic trial knowing that it took 66 seconds to react.

2S2O32-(aq) + I3-(aq) 3 I -(aq) + S4O62-(aq)

Tip: Use your blackboard notes/manual if needed.

(Provide your answer in scientific notation and with two sig figs) Example: if answer is 0.00004 then input 4.0e-5 or 4.0E-5

3.03E-7

Question 3

Given the following data, calculate the (mol I3-) produced.

Moles of S2O32-, consumed: 0.00011

2S2O32-(aq) + I3-(aq) 3 I -(aq) + S4O62-(aq)

Hint: Use a mole to mole ratio from the balanced equation.

Tip: Use your blackboard notes/manual if needed.

(Provide your answer in scientific notation and with two sig figs.) Example: if answer is 0.000065 then input 6.5e-5 or 6.5E-5

5.5E-5

Question 4

Match the following correctly.

Boiled, deionized water

Added to adjust the total volume of each test soluton.

Buffer

Added to maintain a constant pH.

0.02M Na2S2O3

Added to show the appearance of I3- or depletion of thiosulfate ion.

Starch

Removes I3-as it is generated in the reaction.

Rate law

k[A2]p[B2]q

p

Determined from slope of plot of log (rate) vs log [I-]

q

Determined from slope of plot of log (rate) vs log [H2O2]

Question 5

Given the following data, calculate the moles of S2O32- consumed.

Molar concentration of Na2S2O3: 0.02 mol/L

Volume of Na2S2O3: 7 mL

Tip: Use your blackboard notes/manual if needed.

(Provide your answer in scientific notation and with two sig figs) Example: if answer is 0.00002 then input 2.0e-5 or 2.0E-5

1.4E-4

Given that 4.0x10-5 moles of S2O32- were consumed, calculate the Rate for the kinetic trial knowing that it took 66 seconds to react.

2S2O32-(aq) + I3-(aq) 3 I -(aq) + S4O62-(aq)

Tip: Use your blackboard notes/manual if needed.

(Provide your answer in scientific notation and with two sig figs) Example: if answer is 0.00004 then input 4.0e-5 or 4.0E-5

3.03E-7

Explanation / Answer

Question 1:-

From the given balanced chemical equation we can say that

Rate of reaction=rate of consumption of S2O32-/2

Rate of consumption of S2O32-=4×10-5/66=6×10-7

Rate of reaction=3×10-7

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