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Explanation of how you got the values and what that value stands for should also

ID: 487249 • Letter: E

Question

Explanation of how you got the values and what that value stands for should also help me understand the problem.detailed explanations and correct answer are appreciated.I have two hours to answer this question.

The decom on at soacLa was measured as a we yields straight In elopc -i, 42 x line wuth a what lie halt lite ot two reachon ltow long take ho, tle concentra han of SO 2 Cl 2 to decrease to 2solo the inihal Concen ha H am lang will take for he concen hation te at 002 Cl 2 is oom diced noncen hahon alter wha.

Explanation / Answer

2. t1/2   = 0.693/K

            = 0.693/1.42*10-4

            = 4880sec

3. K    = 2.303/t log[a/a-x]

      t   = 2.303/Klog[a/(a-x)]

          = 2.303/1.42*10-4 log100/(100-25)

           = 2.303*0.1249/1.42*10-4

           = 2025sec

c. K    = 2.303/t log[a/a-x]

      t   = 2.303/Klog[a/(a-x)]

     t    = 2.303/1.42*10-4log1/0.78

          = 2.303*0.1079/1.42*10-4

          = 1749sec

4. K    = 2.303/t log[A0]/[A]

   1.42*10-4    = 2.303/2*102 log1/[A]

log1/[A]       = 1.42*10-4 *2*102/2.303

                       = 0.01233

1/[A]                = 100.01233

1/[A]               = 1.02879

[A]                = 1/1.02879 = 0.972M

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