PLEASE HELP & SHOW ALL WORK! In the lab you measure a clean dry crucible and cov

Question

PLEASE HELP & SHOW ALL WORK! In the lab you measure a clean dry crucible and cover to be 24.36 grams. You obtain a 2cm piece of pure magnesium metal. After sand papering the magnesium you place it in into your crucible and the mass of crucible, cover and magnesium masses out to be 24.66 grams. You observe that the magnesium is gray and shiny. you heat the crucible gently at first then vigorous for 10 minutes until the magnesium ignites. After the crucible cools you add a few drops of distilled water and heat again. The mass of the magnesium compound, crucible, and cover masses out to be 24.85 grams. What is the empirical formULa of the compound? Show all work and units.

1) MAss of the Mg

2) Mass of the MgO

3) Mass of 0

4) Moles of Mg & Moles of O

5) Show mole to mole MgxOy

6) Empricial Formula of compound

Explanation / Answer

Mass of crucible = 24.36 g

mass of crucible + magnesium = 24.66g

Thus mass of magnesium metal = 24.66-24.36 = 0.30 g

1) mass of Mg = 0.30 g

mass of crucible + Magnesium oxide = 24.85g

2) mass of magnesium compound = 24.85 -24.36

= 0.49 g

mass of oxygen in the compound = mass of magensium compound - mass of agnesium

= 0.49g - 0.30g

= 0.19g

Thus mass of O in compound = 0.19 g

to calculate the empirical formula

element Mg O

mass 0.30g 0.19g

moles (mass/at.mass) 0.3/24 =0.0125 0.19/16=0.0119

ratio of moles 1.05 1.0

Thus the empirical formula of magensium compound = Mg1O1

= MgO

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