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16.50 For each of the following solutions, calculate the initial pH and the fina

ID: 487410 • Letter: 1

Question

16.50

For each of the following solutions, calculate the initial pH and the final pH after adding 0.0150 mol of NaOH

For 240.0 mL of a buffer solution that is 0.205 M in HCHO2 and 0.300 M in KCHO2, calculate the initial pH and the final pH after adding 0.0150 mol of NaOH(Ka=1.8104).

Express your answers using two decimal places separated by a comma.

For 240.0 mL of a buffer solution that is 0.2922 M in CH3CH2NH2 and 0.2622 M in CH3CH2NH3Cl, calculate the initial pH and the final pH after adding 0.0150 mol of NaOH(Kb=5.6104).

Express your answers using two decimal places separated by a comma.

Explanation / Answer

a) volume of buffer = 240 mL

[acid] = 0.205 M and [conjugate base] = 0.3

Ka of acid = 1.8x10-4

initial pH calculation

pH of a buffer is given by Hendersen equation as

pH = pKa + log [conjugae base]/[acid]

= [4 - log 1.8] + log [0.3/0.205]

= 3.905

Now 0.0150mol of NaOH is added to this solution

the reaction is

HA + OH - ---------> A -   + H2O

240x0.205 0 240x0.3 - initial mmoles

15 change

34.2 0 64.2 - mmoles after addition   

Thus new pH = 3.74 + log 64.2/34.2

= 5.617

b) [base] = 0.2922 M and [conjugate acid ] = 0.2622M and Kb = 5.6x10-4

Thus pOH = pKb + log [conjugate acid]/[base]

= [4-log 5.6] + log 0.2622/0.2922

= 3.2047

thus pH = 14-3.2047

= 10.795

Now pH after adding 0.015 mol NaOH

BH+ + OH- ----------> B + H2O

240x0.2622 0 240x 0.2922 - initial mmoles

15 change

47.928 0 85.128 mmoles after addition

Thus the pOH = [4-log5.6] + log 47.928/85.128

=3.0024

and the pH = 10.99

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