How many yds^3 are in 7.056 tons of Fe ore? d_Fe ore = 7.5 g/m^3 Ans: 1.1173 tim

Question

How many yds^3 are in 7.056 tons of Fe ore? d_Fe ore = 7.5 g/m^3 Ans: 1.1173 times 10^2 yds^2 How many tons of H_2O are in 8.08 times 10^-20 miles of ocean water? d_H_2O = 9.970 times 10^-1 g/ml. Ans: 3.698 tons How many gallons of Hg are in 9 tons? d_Hg = 13.6 g/cm^3 Ans: 1.588 times 10^2 gal Specific Heat: How many Joules of heat would be needed to raise the temperature of 15 tons of W from 2 degree C to 6, 152 degree F? c_W = 2.64 times 10^-2 J/g- degree C Ans: 1.2559 times 10^10 Joule What would the final temperature of 2.500 times 10^4 gallons of ethanol, initially at 103 degree F, be if it absorbed 1.8 times 10^17 ergs of heat ans: 23 degree C c_ethanol = 2.464 J/g middot degree C; d_ethanol = 7.91 times 10^-1 g/cm^3

Explanation / Answer

A) Density:

Weight of Fe is = 7056 tonns

= 7056 * 106 grams

Volume of Fe = mass/Density

= 7056 * 106/ 7.5

= 940.8 * 106 cm3

We know that 1 cm3 = 1.308 * 10-8

Therefore Final Volume is, = 940.8 * 10-6 * 1.308 * 10-8

= 1117.3 yds3

b. Volume of water = 8.08 *10-10 miles3

Weight of water = Density * Volume

= 0.9970 (g/ml) * 8.08 * 10-10 (miles3)

Convert miles3 into ml

1 mil3 = 4.168 * 1015

Therefore 8.08 * 10-10 miles3 = 3367890.9 ml

Weight of water = 0.9970 *  3367890.9

= 3357787 grams = 3.3577 tons

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