Could you help me please I have balanced it but I do not what I should do to get

Question

Could you help me please I have balanced it but I do not what I should do to get the right answer

Aluminum hydroxide is a base that is the active ingredient in some over-the-counter antacids. Suppose you have 22.0mL of 0.170M HCl solution in a flask and you add an antacid tablet to the HCl. After allowing the antacid to react with the HCi solution, you titrate the solution with 0.20 M NaOH. It requires 8.45 mL of NaOH to reach the end point. How many moles of HCI were neutralized by the antacid tablet? mol

Explanation / Answer

moles of HCl present initially = M(HCl)*V(HCl)
= 0.170 M * 22.0 mL
= 3.74 mmol

moles of HCl neutralised by NaOH = moles of NaOH
= 0.20 M * 8.45 mL
=1.69 mmol

This means that,
Remaining HCl were neutralised by antacid

mol of HCl neutralised by antacid = 3.74 mmol - 1.69 mmol
= 2.05 mmol
= 0.00205 mol

Answer: 0.00205 mol

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