Circle the questions that have been, assigned. The crucible is not fired, as the

Question

Circle the questions that have been, assigned. The crucible is not fired, as the procedure suggests, but had retained some impurities from previous use (or it could be oily smudges from fingers). The mass of the "dirty" crucible is recorded. However, the impurities are burned technique error? Explain. Javier forgot to polish the magnesium metal. Will the reported mole ratio of magnesium to oxygen be too high or too low as a result of his error? Explain. The burning of the magnesium becomes uncontrolled (it burns brightly). Oops! Will the reported mole ratio of magnesium to oxygen be too high or too low as a result of this technique error? Explain. in a hurry to complete the experiment, Sylvia did not allow all of the magnesium to react. Will her reported magnesium to oxygen ratio be reported too high or too low? Explain. The sample is not completely thermally decomposed in the procedure. Will the mole ratio of CaO to CO_2 be too high or too low? Explain. The original sample is not pure, but is contaminated with a thermally stable compound. Will the reported mole ratio of CaO to CO_2 be too high, too low? or unaffected? Explain. in an oversize in the experiment Jamie did not add the 4-5 additional drops of 6 M HNO_3. As a result, will high or too low in the final product? Explain. Spattering does occur and some of the sample is lost onto the laboratory bench. Will the reported mole ratio of tin to oxygen be too high? too low. or unaffected? Explain.

Explanation / Answer

1) The crucible weight will remain unchanged because pre-weighed crucible is subtracted from after ignition weight.
   So, it does not matter if the impurities remain or convert to some gaseous products, either way reported mass
will remain unchanged.

7) Number of moles per volume will change since the HNO3 is short by certain drops. It may increase or decrease
basing upon this factor.

8) The reported mass will be less due to spattering therefore the mole ratio of tin to oxygen would be high.

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