What is the element oxidized, reduced, oxidizing agent, reducing agent and numbe

Question

What is the element oxidized, reduced, oxidizing agent, reducing agent and number of electrons transferred of the following
I2 + 2Na2S2O3 > Na2S4O6 + 2NaI
3Ag2S + 8HNO3 > 6AgNO3 + 2NO + 3S + H2O
2C2H6 +7O2 > 4CO2 + 6H2O
BaCl2 + Na2SO4 > 2NaCl + BaSO4
2Al + 3CuSO4 > 3CU + Al2(SO4)3
2NO + O2 > 2NO2
H2CO3 > CO2 + H2O
Zn + 2HCl > ZnCl2 + H2
2K2Cr2O7 + 2H2O + 3S > 4 KOH + 2Cr2O3 + 3 SO2
2MnO4 + 5Cu + 16H+ > 5Cu^2+ + 8H2O
Na2S + 2AgNO3 > Ag2S + 2NaNO3 What is the element oxidized, reduced, oxidizing agent, reducing agent and number of electrons transferred of the following
I2 + 2Na2S2O3 > Na2S4O6 + 2NaI
3Ag2S + 8HNO3 > 6AgNO3 + 2NO + 3S + H2O
2C2H6 +7O2 > 4CO2 + 6H2O
BaCl2 + Na2SO4 > 2NaCl + BaSO4
2Al + 3CuSO4 > 3CU + Al2(SO4)3
2NO + O2 > 2NO2
H2CO3 > CO2 + H2O
Zn + 2HCl > ZnCl2 + H2
2K2Cr2O7 + 2H2O + 3S > 4 KOH + 2Cr2O3 + 3 SO2
2MnO4 + 5Cu + 16H+ > 5Cu^2+ + 8H2O
Na2S + 2AgNO3 > Ag2S + 2NaNO3
I2 + 2Na2S2O3 > Na2S4O6 + 2NaI
3Ag2S + 8HNO3 > 6AgNO3 + 2NO + 3S + H2O
2C2H6 +7O2 > 4CO2 + 6H2O
BaCl2 + Na2SO4 > 2NaCl + BaSO4
2Al + 3CuSO4 > 3CU + Al2(SO4)3
2NO + O2 > 2NO2
H2CO3 > CO2 + H2O
Zn + 2HCl > ZnCl2 + H2
2K2Cr2O7 + 2H2O + 3S > 4 KOH + 2Cr2O3 + 3 SO2
2MnO4 + 5Cu + 16H+ > 5Cu^2+ + 8H2O
Na2S + 2AgNO3 > Ag2S + 2NaNO3

Explanation / Answer

1)

2Na2S20 3 + I2 = Na2S4O6 +2NaI

Oxidation half reaction 2Na2S203 => Na2S4O6 + 2 e-

Reduction half reaction I2 + 2 e- => 2NaI

In Na2S2O3, 2 Na’s = +2,

S2O3 = -2, 3 O’s = -6, 2 S’s = +4, S = +2

+2 + (2 * +2) + (3 * -2) = +2 + +4 + -6 = 0

In Na2S4O6, 2 Na’s = +2,

S4O6 = -2

6 O’s = -12, so 4 S’s = +10

S = +2.5

S+2 is oxidized to S+2.5

I 0 is reduced to I-1

Oxidizing reagent I2

Reducing agent Na2S20 3

Number of electrons transferred = 2e-

2)

3Ag2S + 8HNO3 ------> 6AgNO3 + 2NO + 3S + H2O

Oxidized - S-2 - 2 e- S0

Reduced- N5 + 3 e- N2

Oxidizing reagent – HNO3

Reducing agent – Ag2S

Number of electrons transferred = 6e-

3)

2C2H6 +7O2 -----> 4CO2 + 6H2O

C is oxidized and O is reduced

(The oxidation number of carbon changed from –3 to +4.The oxidation number of oxygen changed from 0 to –2)

Oxidizing reagent – HNO3

Reducing agent – Ag2S

4) BaCl2 + Na2SO4 -----à 2 NaCl + BaSO4

Reactants are: Ba+2, Cl -1, Na +1, SO4 -2

Products are: Ba +2, SO4 -2, Na +1, Cl -1

So there were no changes in oxidation states for any species. It is double displacement reaction.

5) 2Al + 3CuSO4 ----------> 3CU + Al2(SO4)3

Oxidation - loss of electrons, and an increase in oxidation number

2(Al --> Al3+ + 3e-) -- Oxidation half-reaction

3(Cu2+ + 2e- --> Cu) -- Reduction half-reaction

Al is oxidized and

Cu is reduced

CuSO4 is Oxidizing reagent

Al is reducing agent

Number of electrons transferred = 6e-

6)2NO + O2 --- > 2NO2

NO is going through oxidation, and is the reducing agent.

O2 is reduced and is the oxidation agent.

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