Ethylenediamine (shown below) is a chelate that is typically abbreviated as \"en

Question

Ethylenediamine (shown below) is a chelate that is typically abbreviated as "en" The formation constants, K_F, of octahedral Ni^2+ complex ions at 25 degree C are: [Ni(en)_3]^2+ 2 times 10^18 [Ni(NH_3)_6]^2+ 4 times 10^8 Write the reactions for the formation and the formation constants (in terms of concentrations) for each complex ion The delta H_f of the two complex ions are the same to two significant figures. How do you explain the difference in formation constants? If NH_3 were added to an aqueous solution of [Ni(ew)_3]^2+ such that both concentrations were initially 1 M after mixing, what would happen? Write the reaction and discuss on which side the equilibrium would lie, and why. If ethylenediamine were added to an aqueous solution of [Ni(NH_3)_6]^2+ such that both concentrations were initially 1 M after mixing, what would happen? Again, write the reaction and discuss on which side the equilibrium would lie, and why.

Explanation / Answer

[Ni(H2O)6] 2+ (aq) + 6 NH3 (aq) [Ni(NH3)6] 2+ (aq) + 6 H2O (l)

[Ni(H2O6]^2+ +3en [Nien3]^2+ + 6H2O

b) both have different ligands. en and NH3. Hence they have different formation constants though they have same heat of formation

c) Ni2+ + 4 NH3 === [Ni(NH3)4] 2+

[Ni(NH3)4] 2+ concentration will increase

equilibrium will be towards right

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