N2(g) + 3 H2(g) rightarrow 2 NH_3(g) Rate = +3 Delta[H_2]/Delta t Rate = - 3 Del

Question

N2(g) + 3 H2(g) rightarrow 2 NH_3(g) Rate = +3 Delta[H_2]/Delta t Rate = - 3 Delta[H_2] Rate = + 1/3 Delta [H_2]/Delta t Rate = - 1/3 Delta[H_2]/Delta t It is not possible to determine without more information. What are the units of A; that are consistent with the following rate law? Rate = k ppm/year 1/year 1/(ppm middot year) ppm^2/year year/Carbon-14 has a half-life of 5720 years and this is a first order reaction. If a piece of wood initially had 1.80 times 10^-4 moles of carbon-14, then how old is it when 9.00 times 10^-5 moles of carbon-14 remain? 11440 years 5720 years 5556 years 2375 years What data should be plotted to show that experimental concentration data fits a straight line for zero order reaction? 1/[reactant] vs. time [reactant] vs. time ln[reactant] vs. time ln(k) vs. I/T ln(k) vs. E_a The first-order decomposition of cyclopropane has a rate constant of 6.7 times 10^-4 s^-1. If the initial concentration of cyclopropane is 1.33 M, what is the concentration of cyclopropane after 0.43 M 0.15 M 0.86M 0.94 M 0.67 For a reaction, what generally happens if the temperature is decreased? A decrease in k occurs, which results in a faster rate. A decrease in k occurs, which results in a slower rate. An increase in k occurs, which results in a faster rate. An increase in k occurs, which results in a slower rate. There is no change with k or the rate. A reaction is found to have a rate constant of 3.36 times 10^4 M^-1 s^-1 at 344 K and a rate constant of 7.69 M^-1 s^-1 at 219 K Determine the activation energy for this reaction. 4.20 times 10^4 J/mole 1.25 times 10^4 J/mole 1.15 times 10^4 J/mole 2.38 times 10^4 J/mole 5.82 times 10^4 J/mole

Explanation / Answer

Q12

rate of reaction with respect to H2

so... for 1 reaction, we have 3 moles

then, as 3 moles of H2 react, 1 mol of N2 is dissapearing as well

so ratio is

1:3 or 1/3

so

RAte = -1/3*d[H2]/dt

Q13

For RAte = k

note that

Rate = M/s ALWAYS

so

K = same units as Rare

so

K = M/s or --> Concentration per time

a, is correct

b, can't be, no concentration

c, can't be, both are dividing,

d, can't be, there is a square

e, can't be, time is on top

Q14

apply half life equation

A = A0*(1/2)^(t/HL)

9*10^-5 = (1.8*10^-4)(1/2)^(t/5720)

solve for t

ln((9*10^-5) / (1.8*10^-4)) / ln(0.5 ) = (t/5720)

1 = t/5720

so

t = 5720 years

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