The boiling points of water and 2-methyl-2-propanol are 100 degree C and 82.2 de
ID: 490398 • Letter: T
Question
The boiling points of water and 2-methyl-2-propanol are 100 degree C and 82.2 degree C respectively, Which liquid has a lower vapor pressure at a given temperature and WHY? Is it possible to completely separate these two liquids by simple distillation? Why? A Student, during an extraction experiment lost track of which layer was the aqueous phase. How could the student distinguish between the layers if their densities were not known? Why must the stopper be removed from the separatory funnel before the lower layer is drained off during extraction?Explanation / Answer
c)
(i) Water has the lower vapor pressure than the 2-methyl-2-propanol.its because the boiling point of the water is higher than the 2-methyl-2-propanol. Intermolecular forces in 2-methyl-2-propanol are weak than water. Therefore it can easily escape from the surface. Its mean it will evaporate easily.
(ii) It is impossible to separate completely water and 2-methyl-2-propanol from a mixture.it is because there are no large different between boiling temperate. So when boiling the mixture at some temperature there is chance to evaporate both water and 2-methyl-2-propanol molecule.
d)
(i) After separation of both aqueous and organic layer water can be added to the separation funnel. if a volume of a layer become high it’s the aqueous layer. This is because water molecules are polar molecules therefor those molecules are dissolve in aqueous layer.
(ii) When mixing the mixture in separation funnel; a pressure is build up inside the funnel. so when draining the liquid from separation funnel without removing the stopper. Liquid will not drain due the pressure. It’s because pressure will not allow to drain the liquid.
When stopper is removed the pressure will removed from funnel.so liquid can drain.
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