echemical Reactions How many milliliters of 0.132 MHChou solution B) 0.0335 are

Question

echemical Reactions How many milliliters of 0.132 MHChou solution B) 0.0335 are needed to neutralize 50.00 mL of 0.0789 NaOH? 23 The net ionic equation for the E) 29.9 A) H+ OH- H20 aqueous solutions of HF and KOH is B) HF KOH H20 K+ F- H20 K+ F- D) HF OH- H20 F- E) HF K+ H20 KF 24) which of the following are strong electrolytes? 1) HCI 2) HC2H302 4) KCI A) 1, 2, 4 B) 1,4 CO 1, 3, 4 DO 1, 2, 3, 4 E) 2,4 25) of the species below, only is not an electrolyte. A) NaCl B) Rb2SO4 D) KOH 26) Which solution contains the largest number of moles of chloride ions? A) 30.00 mL of 0.100M CaC12 B) 7.50 mL of 0.500M FeC13 25.00 mL of 0.400M KCI D) 400 mL of 1.000M NaCl E) 10.0 mL of 0.500M Bac12 27 How many moles of K+ are present in 33 mL of a 1.27 M solution of K3PO? A) 0.145 B) 3.70 C) 1.31 D) 0.436 28) The compound HCIOM is a A) strong base B) weak base C strong acid D) weak acid compound 29) Which of the following is not an exchange reaction? A) 2NaN3 (s) 2Na (s) 3N2 (g) 2HNO3 (aq) Caco3 (s) Nac2H302 (aq) HNO3 (aq) HC2H302 (aq) NaNO3 (aq) D) AgNO3 (aq) HCl (aq) AgCl (s) HNO3 (aq) 23.9 mL of the base to reach the endpoint of the titration. What was the concentration (M) of the acid? A) 0.0051 B) 1.02 0.227 D) 0.0204 E) 0.0102

Explanation / Answer

Answer(22)

perchloric acid is monoprotic, so this is a Ka1 only.
Find moles of NaOH first: 50.00mL/1000 = 0.05L x 0.0789M = 0.003945 moles.
Do a solve for x problem to find what volume of molarity needed:
(0.132 mol/L)(x) = (0.003945 moles)
This leaves liters:
0.0299 L x 1000 = 29.9 mL

So answer is (E) 29.9 mL

Answer(23)

HF and KOH will undergo a double replacement reaction if the two aqueous solutions are mixed:

HF(aq) + KOH(aq) --> HOH(l) + KF(aq)

HF is not a strong acid, so it will not be written as being dissociated in the ionic equation.

KOH is a strong base, so it will completely dissociate in solution.

H2O cannot be written as separate ions in an ionic equation.

KF is a soluble salt, so it will dissociate completely in water.

Therefore, to write the ionic equation:
HF(aq) + K+ + OH- --> H2O(l) + K+ + F-

The only spectator ion present (species left unchanged on both sides of the ionic equation) is K+. Therefore, the net ionic equation is:

HF(aq) + OH- --> H2O(l) + F-

So answer is (D)

Answer (24)

HCl is a strong acid; it dissociates completely to form H+ and Cl- ions. Thus, it is a strong, rather than weak, electrolyte.
CH3COOH is acetic acid, a weak acid. Only some of it will dissociate (to H+ and acetate ions), so it will only be a weak electrolyte.
NH3 will react with water as a weak base: NH3 + H2O <----> NH4+ + OH-
It will thus also be a weak electrolyte.
KCl is a soluble ionic compound, and as such, it will be a strong electrolyte.

So answer is (B) 1,4

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