Water was added to take the volume of the mixture to 50.0 mL. MW of Ba(oH is 171

Question

Water was added to take the volume of the mixture to 50.0 mL. MW of Ba(oH is 171 g/mol. and to get pace below is for calculations and/or reactions you might need to do before answering the questions redit. (Very similar to study assignment problems.) Y ol mol Ba (OH) r all the (ions, acids, salts) present in the solution after rea ccur. Make sure to apply to solubility and dissociation rules so as to provide the correct net ionic representation and your work above has provide support for your choices! H20, H P2 b) What is the FINAL concentration of H in solution once all reactions are finished?

Explanation / Answer

The reaction is

H2SO4 + Ba(OH)2 --------------> BaSO4 (s) + H2O

25 x1.00 1.71x1000/171 0 0 initial mmol

= 25 =10

15 0 15 - after reaction

[H2SO4] after reaction = 15/50 =0.3 M

[H+] after reaction = 2 x 15/50 (since H2SO4 is diprotic acid)

=0.6 M

After the reaction the species present are BaSO4, H+ , H2O

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.