Consider titrating CH_3COOH with standard NaOH (delivered from the burette) to a

Question

Consider titrating CH_3COOH with standard NaOH (delivered from the burette) to answer the following question(s). How would the pH be determined for the aqueous solution in the titration above at the equivalence point? The pH is determined by solving for the pH of an acidic salt. The pH would equal 7.0 at the equivalence point. The pH is determined by the Henderson-Hasselbalch equation. The pH is determined by taking -log[CH_3COOH]_original. The pH is determined by solving for the pH of a basic salt.

Explanation / Answer

A:- The pH is determined by solving for the pH of a basic salt,

CH3COOH(aq)   +   H2O(l)   <=========>   CH3COOH(aq)    +   OH^-(aq)

Kb = [CH3COOH][OH^-] / [CH3COO^-]

pOH = -log[OH^-]

pH = 14.0 - pOH

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