A buffer is made by dissolving H_3PO_4 and NaH_2PO_4 in water. (10.7) Write an e

Question

A buffer is made by dissolving H_3PO_4 and NaH_2PO_4 in water. (10.7) Write an equation that shows how this buffer neutralizes added acid. Write an equation that shows how this buffer neutralizes added base. A buffer is made by dissolving HC_2H_3O_2 and NaC_2H_3O_2 in water. (10.7) Write an equation that shows how this buffer neutralizes added acid. Write an equation that shows how this buffer neutralizes added base. Calculate the volume, in milliliters, of a 0.150 M NaOH solution needed to neutralize each of the following: (10.6) 25.0 mL of a 0.288 M HCl solution 10.0 mL of a 0.560 M H_2SO_4 solution 5.00 mL of a 0.618 M HBr solution Calculate the volume, in milliliters, of a 0.215 M KOH solution needed to neutralize each of the following: (10.6) 2.50 mL of a 0.825 M H_2SO_4 solution 18.5 mL of a 0.560 M HNO_3 solution 5.00 mL of a 3.18 M HCl solution A 0.205 M NaOH solution is used to titrate 20.0 mL of a solution of H_2SO_4. If 45.6 mL of the NaOH solution is required, what is the molarity of the H_2SO_4 solution? (10.6) H_2SO_4(aq) + 2NaOH(aq) rightarrow 2H_2O(l) + Na_2SO_4(aq) A 10.0-mL sample of vinegar, which is an aqueous solution of acid, HC_2H_3O_2, requires 10.5 mL of a 0.500 M NaOH in a titration. What is the molar-

Explanation / Answer

Q10.81

a)

the equation that will buffer/neutralize the acid, H+ is given by:

H3O4 --> this can't neutalize acid, since it is already a strong acid

NaH2PO4 --> will form Na+ and H2PO4- in solution

Note that

H2PO4-(aq) + H+(aq) = H3PO4(aq)

so this neutralizes the addition of H+

for

b)

the equation that buffers and neutralizes the base, i.e. OH-

is given by the strong acid

H3PO4(aq) + OH-(aq) --> H2O(l) + H2PO4-(aq)

note that H2PO4- is now formed, so it increases its conjugate base

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