Part C: Heat of Neutralization (7 marks) Concentration of HCI concentration of N

Question

Part C: Heat of Neutralization (7 marks) Concentration of HCI concentration of NaoH Trial 2 Trial 3 Trial 4 Trial 1 21.6 21 u 22 A. Mass of calorimeter (g) B. Mass HCI and Calorimeter (g) Mass calorimeter, HCl and NaoH (g) 1. Mass HCI (g) (B A) 19.6 7 13.5 D2. Mass NaoH (g) (C-B) 20.3 20.2 20. 20.3 Mass of Solution (D1 -D2) Initial Temperature HCI measured C) 27 o 22.0 21.o 23. (thermometer 1) Initial Temperature HCI corrected C) 220 220 122. Initial Temperature NaoH measured (thermometer 2) Initial Temperature NaoH corrected E. Average Initial Temperature corrected C) Final Temperature measured (c) (thermometer 1) ?O. O 29.3 29.1 22.5 F. Final Temperature corrected C) G. Temperature change corrected (F-E)

Explanation / Answer

Part B

Thermometer 1 shows water ice bath temperature to be 0.1oC.

Therefore, Corrected temperature of cold water = (22.5 -0.1)oC = 22.4oC

Thermometer 2 shows water boiling temoerature to be 96oC i.e. 4oC lower

Therefore, corrected temperature of Hot water = (47.5 + 4)oC= 51.4oC

Final temperature of water = (39.2 - 0.1)oC = 39.1oC

Part C

1. Measured temperature = 52.1 oC

Using ice-point method,

deviation shown = -0.7oC

Therefore, corrected tempertaure = (52.1 +0.7)oC = 52.8oC

Using boiling point method,

deviation shown = (100-98.8)oC = 1.2oC

Therefore, corrected temperature = (52.1+1.2)oC = 53.3oC

Average corrected temperature = (52.8 + 53.3) /2 = 53.05 oC

Initial temperature HCl measured oC(Thermometer 1) 23 22 21 23 Initial temperature HCl corrected oC(measured temp - 0.1oC ) 22.9 21.9 20.9 22.9 Initial temperature NaOH measured oC(Thermometer 2) 22 24 23 22 Initial temperatureNaOH corrected oC(measured temp + 4oC) 26 28 27 26 E.Average initial temperature corrected oC 24.45 24.95 23.95 24.45 Final temperature measured oC(Thermometer 1) 30.0 29.9 29.1 27.5 F. Final temperature corrected oC (measured temp - 0.1oC ) 29.9 29.8 29.0 27.4 Temperature change corrected( oC) (F-E) 29.9-24.45 =5.45 29.8-24.95 = 4.85 29.0-23.95 = 5.05 27.4-24.45 = 2.95

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