Conide the following system at equilibrium. a.) how will increasing the concentr
ID: 492672 • Letter: C
Question
Conide the following system at equilibrium. a.) how will increasing the concentration of H2 shift the equilibrium? b.) how will increasing the concentration of H2 S shift the equilibrium? Print Calculator Periodic Table Question 16 of 26 A Sapling Learning an earning Consider the following system at equilibrium. 2H a) How will increasing the concentration of Ha shift the equilibrium? O to the right O to the left O no effect b How will increasing the concentration of H2s shift the equilibrium? O to the right O to the left O no effect c) How will adding a catalyst shift the equilibrium? to the right to the left no effectExplanation / Answer
According to LeChatelier's pricciple,
1) addition of reactants shifts the equilibrium to the right.
2) addition of products shifts the equilibrium to the left.
We know that catalyst has no effect on the position of equilibrium.
Therefore,
a) Since H2 is the reactant, increasing the concentration of H2 shifts the equilibrium to the right.
b) Since H2S is the product, increasing the concentration of H2S shifts the equilibrium to the left.
c) ans = no effect
catalyst has no effect on the position of equilibrium.
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.