Freezing point of solvent _____ M.W. of known solute _____ Weight of known solut

Question

Freezing point of solvent _____ M.W. of known solute _____ Weight of known solute _____ Weight of solvent _____ Freezing point of solution _____ Freezing point depression (Delta T) _____ Molality of solute (m) _____ K_f (-Delta T/m) _____ Unknown number _____ Weight of unknown solute _____ Weight of solvent _____ Freezing point of solution _____ Freezing point depression (Delta T) _____ Molality of solute (= Delta T/K_f) _____ M.W. of unknown _____ Show calculation: Accepted M.W. (if known) _____ Percent error _____

Explanation / Answer

THE IMAGE AND WRITING IS NOT CLEAR, BUT TO THE EXTENT UNDERSTOOD IT IS DONE

Molality of the solution = (0.66/122) x (1000/28)

                                    == 0.3 (so part B is wrong)

now depression in hte freezing point = Kf x molality

           so freezing point constant, Kf = 274/ 0.3 = 3.33 K /molal    note 10c   = 274 k

PART C

MOLALITY OF THE SOLUTION = freezing point depression / constant

       IMAGE WRITING IS NOT UNDERSTOOD, SORRY IT MUST BE CLEAR.

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