Calculate the solubility of calcite at 15 degrees C in water in equilibrium with

Question

Calculate the solubility of calcite at 15 degrees C in water in equilibrium with CO2 at 3x10^-3 atm pressure. Set up the equations based on the dissociation of carbonic acid and solve for the activity of H+. Specify the concentrations of all ions and express Ca2+ in mg/L. Assume ideality to get an idea of ionic strength, then iterate using Debye-Huckel to get a more accurate determination of concentrations. (At 15 degrees celsius, for the carbonate system, pKa1 = 6.42, pKa2 = 10.43, pKsp = 8.22, and pKCO2 = 1.35)

Explanation / Answer

CaCO3 -------- CaO + CO2

CO2 + H2O ------- H2CO3

Ka = [ H2CO3 ] / [ CO2 ] [ H2O]

pKsp = - log Ksp

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