What data should be plotted to show that experimental concentration data fits a

Question

What data should be plotted to show that experimental concentration data fits a first-order reaction? 1/[reactant] vs time [reactant] vs. Time In[reactant] vs. time In(k) vs. 1/T In(k) vs. E_a The half-life for the second-order decomposition of Hll is 15.4 s when the initial concentration of Hll is 0.67 M. What is the rate constant for this reaction? 1.0 times 10^-2 M^-1_s^-1 4.5 times 10^-2 M^-1_s^-1 9.7 times 10^-2 M^-1_s^-1 2.2 times 10^-2 M^-1_s^-1 3.8 times 10^-2 M^-1_s^-1. If the initial concentration of N_2O_5 is 2.88 M, what is the concentration of N_2O_5 after 12.5 minute? 0.124 M 0.805 M 0.355 M 0.174 M Which of the following reactions would you predict to have the smallest orientation factor? X_2 + Y_2 rightarrow 2 XY NOCI_2 + NO rightarrow 2NOCI cIN_2 + O_2 rightarrow 2 NO N + O_2 rightarrow NO_2 All of these reactions should have nearly identical orientation factors. Given the following proposed mechanism, predict the rate law for the overall reaction 2NO_2 + CI_2 rightarrow 2NO_2CI (overall reaction) NO_2 + CO_2CI + CI slow NO_2 + CI rightarrow NO_2CI fast Rate = k[NO_2][CL_2] Rate = k[NO_2]^2[CI_2] Rate = k[NO_2CI]^2 Identify an homogenous catalyst. 50_2 over vanadium (V) oxide Pd in H_2 gas Pt with methane H_2SO_4 with concentrated HCI N_2 and H_2 catalyzed by Fe

Explanation / Answer

Q10

For first order reaction, we must integrate:

Rate = k*[A]

rate = dCa/dt so

dCa/dt = k*Ca

dCa/Ca = k*dt

integrating

-ln(Ca) + ln(Ca0) = k*dt

so

we require a ln(Ca) vs. time, i.e. Ca = reactant

choose C

Q11

For 2nd order rate:

t 1/2 = 1/(K*Ca0)

where

t 1/2, half life

K, rate constant

Ca0 inital concentration

so, solve for k

k = t 1/2 * Ca0

k = 15.4 * 0.67 = 10.318 1/Ms

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