Which step do you think is the rate-limiting step? Results for Runs 1-6: Run [H
ID: 493665 • Letter: W
Question
Which step do you think is the rate-limiting step?
Results for Runs 1-6:
Run
[H+]
[C6H10O]
[I3-]
Rate (M/min)
Rate Constant
(1/min)
1
0.069
0.074
0.0039
5.76x10-5
1.14x10-2
2
0.14
0.074
0.0039
1.21x10-4
1.20x10-2
3
0.15
0.034
0.0039
6.86x10-5
1.36x10-2
4
0.15
0.069
0.0039
1.17x10-4
1.16x10-2
5
0.15
0.074
0.0024
1.28x10-4
1.18x10-2
6
0.15
0.074
0.0047
1.23x10-4
1.14x10-2
Results for run 6-9
Run
[H+]
[C6H10O]
[I3-]
Temp (°C)
Rate (M/min)
Rate Constant
(1/min)
6a
0.15
0.074
0.0047
21.2
1.07x10-4
9.89x10-3
6b
0.15
0.074
0.0047
20.9
1.23x10-4
1.141x0-2
7a
0.15
0.074
0.0047
30.0
2.49x10-4
2.31x10-2
7b
0.15
0.074
0.0047
30.0
2.65x10-4
2.45x10-2
8a
0.15
0.074
0.0047
40.5
7.14x10-4
6.61x10-2
8b
0.15
0.074
0.0047
40.3
6.66x10-4
6.16x10-2
9a
0.15
0.074
0.0047
1.7
9b
0.15
0.074
0.0047
1.8
1.35x10-5
1.25x10-3
Run
[H+]
[C6H10O]
[I3-]
Rate (M/min)
Rate Constant
(1/min)
1
0.069
0.074
0.0039
5.76x10-5
1.14x10-2
2
0.14
0.074
0.0039
1.21x10-4
1.20x10-2
3
0.15
0.034
0.0039
6.86x10-5
1.36x10-2
4
0.15
0.069
0.0039
1.17x10-4
1.16x10-2
5
0.15
0.074
0.0024
1.28x10-4
1.18x10-2
6
0.15
0.074
0.0047
1.23x10-4
1.14x10-2
The reaction being studied and proposed mechanisms Using the tools describe above, this lab will allow you to determine a rate law for the reaction below, and also determine the activation energy for the rate determining step (the slow step in the mechanism). If the rate law for a reaction does not include a given reactant, then any elementary step that includes that reactant cannot be the rate determining step H2C CH HoC 21 Figure 1: The iodination of cyclohexanoneExplanation / Answer
We know slow step is rate determining step.Also we know slow step is irreversible reaction while fast reaction is reversible.
According to steps that you have shown, step 3 is irreversible reaction so step 3 is rate determining step.
Therefore rate law = K3[C6H10O][I3-]
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