the answer is 1.4E4 for part one, how do we get that? When a 184-gram sample of

Question

the answer is 1.4E4 for part one, how do we get that?

When a 184-gram sample of dolomite, CaMg(CO_3)_2 (s), is heated quickly to 910 K in a 0.50-liter closed container, the pressure rises to 1.2 times 10^2 atm. Under these conditions, the reaction quotient is ______ and the pressure in the container ________ [increases, decreases, remains constant] as the system approaches equilibrium. CaMg(CO_3)_2 (s) rightwardsharpoonoverleftwards harpoon CaO(s) + MgO(s) + 2 CO_2 (g) K_P = 2.5 times 10^4 at 900 K. For answer 1, report your answer with two significant figures. Do NOT include units in your answer. Report your answer in scientific notation with the format 2.2E2 or 2.2E-2. Fill in the correct word or phrase for answer 2.

Explanation / Answer

CaMg(CO3)2 --> CaO + MgO + 2CO2(g)

Kp = 2.5*10^4

calculate Qp:

Qp = (P-CO2)^2

since only CO2 is the gas, the pressure is mainly CO2

so

P-CO2 = 1.2*10^2 atm

substitute

Qp = (P-CO2)^2 = ( 1.2*10^2 )^2 = 14400 = 1.44*10^4

since

Qp < Kp, i.e. 1.44*10^4 < 2.5*10^4 this is not in equilibrium

so the pressure in the container will actually be increased, since it must still produced more gas in order to achieve Qp = Kp

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