At neutral pH Valine can be thought of as a n amphoteric species because it can
ID: 493976 • Letter: A
Question
At neutral pH Valine can be thought of as a n amphoteric species because it can donate the proton from its -COOH group and it can accept a proton on its -NH_2 group. At low pH Valine can act as a diprotic acid (which means that it can donate 2 consecutive protons) and at high pH it can act as a diprotic base (which means it can accept 2 consecutive protons). The titration curve to the right corresponds to the titration of diprotic Valine with 0.1 M NaOH. Use the titration curve to estimate the two pK_ a values of valine. a. 1.4 and 3.4 b. 2.4 and 9.7 c. 2.4 and 6.0 d. 6.0 and 11 e. 9.7 and 11 Which of the following represents valine in its most addle form (as a diprotic acid)? If you have a solution of valine at pH 9.0, approximately how many moles of 0.1 M NaOH can you add before you exceed the buffer capacity? a. 0.0001 moles b. 0.0003 moles c. 0.0005 moles d. 0.0007 moles e. 0.0009 moles At pH 1.8 Valine exists in its most acidic, diprotic form. How many mL of 0.2 M NaOH will you need to add to a solution of valine at pH 1.8 to fully deprotonate the Valine? a. 5 mL b. 10 mL c. 20 mL d. 40 mL e. 60 mLExplanation / Answer
Q28
the titration is for an amino acid, which contains acidic and basic species
so
for the pKa, reclal that ALWAYS
Equivalent Volume = 10 mL
half equivalence = 10/2 = 5 mL
the pH in this point is pretty special since
pH = pKa + log(A-/HA)
and A = HA , so A-/HA = 1, given log(1) = 0
so pH = pKA
the pH at V = 5 mL ---> pH = 2 approx.. nearest answer is 2.4
for the second pK value...
this must be between pHequvalence 1 and pH equivalence 2
so
V1 = 10 mL and V2 = 20 mL
pH in V = 15 mL --> pH = 9.7 approx
so
best answer is B, 2.4 and 9.7
Q29
the most acidic form... will be the specie with most H+ ions present
so
ignoreb and d, since amino groups are not protonated
ignore c, since O- is not protonated as OH
so best answer is A, whic has OH and NH3+ group (most protonated)
For Q30 and Q31
please add the "exceeding" criteria for the buffer, since this could be either pH = +/- 1 or any ohter value
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