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General Chemistry Section 7 Herczogh Manipulating Theoretical. Actual, and Peroe

ID: 494998 • Letter: G

Question

General Chemistry Section 7 Herczogh Manipulating Theoretical. Actual, and Peroent Yields The mass product produced assuring a too Eyeais called the theoretical Part B A chemist anthe neachen and 54 g of What the percent Express your answer as a percent tothree significant figures. percent 58.7 Incorrect: Try Again: 4 attempts remaining The chemst discovers amore encert calaystthat can produce ethylbutyate wth a 780% yeld How many grams would be produced tom 805 gofbutanoc aod and excess emanon Express your answer in grams to three significant gures mass of ethy butyale O

Explanation / Answer

The reaction is

C3H7COOH + C2H5OH -------> C3H7COOC2H5 + H2O

Maass of butanoic acid = 8.05

moles of butanoic acid = 8.05/88

=0.09147

part B )

According to equation 1 mole of acid gves one mole of product ester.

Thus 0.09147 mol of acid gives 0.09147 omoles of ester

Thus mass of ester theroretically = moles x molar mass

= 0.09147molx116 g/mol

= 10.61 g

experimental yield of product =5.45 g

Thus % yield= 5.45x100/10.61

= 51.36 %

part C

With the new catalyst the % yield is78.0%

Thu s the amount of product = 10.61x78/100

= 8.275 g

Thus the amount of product ester that will be produced from 8.05 g of acid = 8.275g