Nitrogen and hydrogen react to form ammonia, like this: N_2(g)+3H_2(g) rightarro
ID: 495007 • Letter: N
Question
Nitrogen and hydrogen react to form ammonia, like this: N_2(g)+3H_2(g) rightarrow 2NH_3(g) Suppose a mixture of N_2, H_2, and NH_3 has come to equilibrium in a closed reaction vessel. Predict what change, if any, the perturbations in the table below will cause in the composition of the mixture in the vessel. Also decide whether the equilibrium shifts to the right or left. Some NH_3 is added. The pressure of N_2 will The pressure of H_2 will to the right to the left (none) Some H_2 is removed. The pressure of N_2 will The pressure of NH_3 will to the right to the left (none) The volume of the vessel is increased. The pressure of NH_3 will to the right to the left (none)Explanation / Answer
The reaction is N2 + 3H2 -----> 2 Nh3
1) some NH3 added
Product is added. ACcording to Le-Chatlier principle the equilibrium responds to reduce [NH3] .
Thus backward reaction is favored and equilibrium shifts to left side.
So [N2 ] and [H2 ] and their pressures increase.
2) Some H2 is removed.
Reactant removal aslo favors back ward reaction.
Thus [N2] increases and [NH3] decreases.so pressure of N2 increases and pressure of NH3 decreases and the equilibrium shofts to the left.
3) Volume of vessl is increased.
The pressure of the container is decreased with increase in volume.
When presure decreases the equilibrium shifts to the side where more number of moles are there. For this reaction left side has more moles .
Thus the equilibrium shifts left side and pressure of ammonia decreases.
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