We\'re given this sheet for the titration of an unknown acid with NaOH. How woul

Question

We're given this sheet for the titration of an unknown acid with NaOH.

How would i go about solving for Mass of acid titrated, moles of NaOH added and Equivalent Weight of acid?

For example, let's say in trial #1

- Volume of acid titrated: 25ml

- Initial Buret Volume: 0.0ml

- Final Buret Volume: 26.0ml

- Concetration of NaOH = 0.125

**we are NOT given the molar mass of the acid only g/L

ment 4: Acid-Base Equi Data Form For Part II Each Student Should Bring This Form To Lab! Group Number: Student Name: Unknown Acid Concentration of NaOH initial buret volume final buret volume Equivalent Weight of Calculation for Mass of acid titrated for titration #1 Calculations for moles of NaOH added for titration #1 Calculation fo E W for titration Calculation for average EW Ave value of Equivalent Weight: Justification for number of trials included in average EW Acid identity. Describe rationale of acid identification below. 22

Explanation / Answer

How would i go about solving for Mass of acid titrated --> relate moles and mass as follows:

Molar Mass of acid = Concentration (g/L) / Molarity (mol/L)

concentration as you stated, is given, so we need to find molaity

Molarity of acid = Molarity of base

Molarity of base = given

mass of acid:

mol of acid = M*V

mass f acid = mol*MW

recall that MW comes from C/M ratio

for

Moles of NaOH added:

mol of base = Molarity f base * Volume of base

Equivalencet weight of acid = Molar weight of acid ( if monoprotic)

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