The enzyme-catalyzed conversion of a substrate at 25C has a Michaelis constant o

Question

The enzyme-catalyzed conversion of a substrate at 25C has a Michaelis constant of 0.034 mol L-1 . The rate of the reaction is 8.64 x 10-3 mol L-1 s -1 when the substrate concentration is 0.290 mol L-1 . What is the maximum velocity of this enzymolysis?

5. 6. The enzyme-catalyzed conversion of a substrate at 250C has a Michaelis constant of 0.034 mol L 1. The rate of the reaction is 8.64 x 10 3 mol LT s when the substrate concentration is 0.290 mol L What is the maximum velocity of this enzymolysis?

Explanation / Answer

The Michaelis-Menten Equation is

V= Vmax[S]/ ( KM+S)

Given V= 8.64*10-3 Mol/L.s

[S] =0.290 Mol/L, KM= 0.034

8.64*10-3= Vmax* 0.290/(0.034+0.290) =Vmax*0.009653

Vmax= 8.64*10-3/0.009653= 0.895 Mol/L.sec

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