Potassium hydrogen phthalate, KHP (actual formula KHC_8H_4O_4 with MM = 204 g/mo

Question

Potassium hydrogen phthalate, KHP (actual formula KHC_8H_4O_4 with MM = 204 g/mol) is somewhat soluble in water at 25 degree C. Its solubility can be represented by this equilibrium reaction: KHP_(s) leftarrow rightarrow K^+_(aq) + HP^-_(aq) An experiment similar to Eq487 was conducted. A 0.30 M aqueous solution of KCI was saturated with KHP. Solid KHP was filtered from the mixture to leave a saturated solution. Samples of the saturated solution were titrated with 0.575 M NaOH solution to yield the following data. Use the data to complete this table: (Please show work. Use separate sheet if necessary.)

Explanation / Answer

Trial 1:

a: Moles = molarity x volume = 0.575 x 0.01581mL = 9.1e-3moles

b: As 1:1 STOICHIOMETRY, moles of HP- = 9.1e-3 moles

c: conc of HP- = moles/volume = 9.1/0.025 = 0.36363M

d: K+ initial = 0.3M ( KCl initial solution)

e: K+ from dissolved KHP = 0.36363M

f: K+ sat = 0.3M + 0.36363M = 0.66363M

g: Ksp = K+sat x HP-sat = 0.66363 x 0.36363 = 0.24

Have a nice day!

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.