Equal volumes of 0.320 M aqueous solutions of formic acid (HCOOH(aq)) and sodium
ID: 499330 • Letter: E
Question
Equal volumes of 0.320 M aqueous solutions of formic acid (HCOOH(aq)) and sodium benzoate (NaC_6H_5COO) are mixed. Write the net ionic equation for the overall reaction that takes place as the system comes to equilibrium. Write acetic acid, benzoic acid or formic acid and their conjugates in the form RCOOH/RCOO. For example, benzoic acid should be written "C_5H_5COOH" NOT "C_6H_5CO_2H". It is not necessary to include states such as (aq). What is the value of the equilibrium constant for this reaction? What is the pH of the resulting solution?Explanation / Answer
1)
CH3COOH ----------------> (CH3COO ) ^ - + H ^ +
NaC6H5COO -------------> Na ^ + + C6H5COO ^ -
CH3 COOH + NaC6H5COO ----------> C6H5COOH + CH3COONa
CH3COOH ----------> CH3COO ^ - + H ^ +
K = [ CH3COOH] / [ CH3COO ] ^ - [H ] ^ +
2) The value of equilibrium constant for the above reaction = 1.6 x 10 ^ - 10
3) PH of the resulting solution = 14 - P[OH]
= 14 - 5.66
= 8.34
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