I\'m not so sure as to what method I would use to solve this type of question. I

Question

I'm not so sure as to what method I would use to solve this type of question. I would appreiciate if you showed the work! I will rate well, thank you!

Solutions Determine the equivalent acid-base equilibrium that results when each of the following pairs of solutions is mixed 25.0 mL of 0.50 M NaOH 12.0 mL of 1.00 M HCI Pick two initial conditions from first four choices. Pick one choice from remaining choices to indicate t of equivalent solution. Select one or more a. Weak acid b. Strong acid c. Weak base d. Strong base e. pH determined by excess concentration of diluted strong acid (some acid used to neutralize base) f. pH determined by excess concentration of diluted strong base g. pH determined by concentration of diluted strong acid h. pH determined by buffer equation (resulting mixture produces a buffer) i.pH determined by conjugate base concentration (equivalent to equivalence point in titration of weak acid) pH determined by excess concentration of diluted strong base (remaining strong base weak conjugate base beyond equivalence point in titration of weak acid)

Explanation / Answer

mmol of base = MV = 25*0.5 = 12.5 mmol of OH-

mmol of acid = MV = 12*1 = 12 mmol of H+

mmol of OH- left = 12.5 - 12 = 0.5 mmol of OH- left

so

pÓH = -log(OH)

therefore:

initial conditions:

- strong acid + strong base react to form water + salt and leftover of base

pH is determined by excess base + dilution ( f)

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