advance study assignment molar mass of an acid. 1. 7.2ml of 6.0M NaOH there are

Question

advance study assignment molar mass of an acid.

1. 7.2ml of 6.0M NaOH there are in 7.2ml of 6.0 M NaOH are diluted with water to a volume of 400.0ml. you are asked to find the molarity of the resulting must be solution.

a. first find out how many moles of NaOH there are in 7.2ml of 6.0 M NaOH. use equation 1. note that the volume must be in liters.

b. since the total number of moles of NaOH is not changed on dilution, the molarity after dilution can also be found by equation 1. using the final volume of the solution. calulate the molarity.

2. in an acid base titration, 21.16ml of an NaOH solution are needed to neutralize 20.04ml of a 0.0997M HCL solution. to find the molarity of the NaOH solution, we can use the following procedures.

a. first note the value of MH+ in HCL solution.

b. find MOH- in NaOH solution equation 3

c. obtain M NAOH from M OH

3. a 0.3012g sample of an unknown monoprotic acid requires 24.13ml of 0.0944 M NaOH of neutralization to a phenolpthalein end point. there are 0.32ml of 0.0997 M HCL used for back titration.

a. how many moles of OH- are used?
how many moles of H+ from HCL?

_____moles OH- _______ moles H+

b. how many moles of H+ are there in the solid acid? use eq 5.

____moles H+ in solid

c. what is the molar mass of the unknown acid? use equation 4.

______g/mol

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Explanation / Answer

1)

M1 = 6.0 M

V1 = 7.2 mL

moles of NaOH = 6 x 7.2 /1000 = 0.0432 moles

V2 = 400.0 mL

from diluted principle :

M1 V1 = M2 V2

6.0 x 7.2 = M2 x 400

M2 = 0.108

Molarity of resulting solution = 0.108 M

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