M- Texas Woman University... x C Chegg study l Guided sol... X /biscm 3145131 mi
ID: 500779 • Letter: M
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M- Texas Woman University... x C Chegg study l Guided sol... X /biscm 3145131 ming-com Ga e now to save a screen shot a apicture Tr A E pling My Assignment Resources 3/29/2017 11:55 PM 38.3/100 3/22/2017 08:28 PM Gradebook o Assignment Information Attempts Score Print Calculator Periodic Table Available From: 3/3/2017 12:00 AM Due Date: 3/29/2017 11:55 PM Map Sapling Learning Points Possible: 95 Grade Category: Graded What is the concentration of S n equilbrium with MnS(s) (Kp 4.6x10 and 0.061 M Mn Description Policies: Number ST- 7.7x 10-13 You can check your answers. You can view solutions when you complete or give up on any que You can keep trying to answer each question until 95 you get it right or give up. You lose 59% of the points available to each answer A Previous Give Up & View Solution Try Again ONext 1Exit Expla in your question for each incorrect attempt at that 10 The solubility expression for MnS is 11 o eTextbook Mn 12 Plug in the given K and IMn? values, then solve for IS o Help with This Topic 13 OWeb Help & Videos 14 o Technical support and Bug Reports 15 4:14 PM Ask me anything 3/24/2017 R3Explanation / Answer
If this is in equilibrium, then
the MnS dissociates as follows:
MnS(s) <-> Mn+2 + S-2
so
Ksp = [Mn+2][S-2]
we do not include the solid, since activity = 1
if we know
Ksp = 4.6*!0^-14
AND
[Mn+2] = 0.061
substitute all into Ksp
Ksp = [Mn+2][S-2]
4.6*10^-14 = 0.061*[S-2]
solve for [S-2]
[S-2] = ( 4.6*10^-14)/0.061 =7.54*10^-13
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